I have a triangle ADB. AD = 2, AB = 3 DB is x. I need to find x. Additional info. AB/BC = BD/BD = AD/BD. Other triangle is DCB. DB is x, DC is 8, CB is y. Booth of triangles are connect by DB. Figure resembles a kite. (Needed to complete 3/y =x/x= 2/x. Is this correct?)

To find the value of x, we can use the given information about the triangles and set up equations based on the ratios mentioned.

Let's consider triangle ADB first. We have the following given information:
AD = 2
AB = 3
DB = x

We are also given the ratio AB/BC = BD/BD = AD/BD.

Since AB/BC = AB/BD and BD = x, we can write:
AB/BC = AB/BD
3/BC = 3/x
x/BC = x/3

Similarly, we are given AD/BD = AB/BD, so we can write:
AD/BD = AB/BD
2/x = 3/x

From these two equations, we can conclude that:
x/BC = x/3 [equation 1]
2/x = 3/x [equation 2]

Moving forward, let's consider triangle DCB. We have the following given information:
DB = x
DC = 8
CB = y

We are given that both triangles ADB and DCB are connected by the side DB.

Now, if we observe the figure, we can see that the two triangles, ADB and DCB, form a kite-like shape. In a kite, the diagonals intersect at right angles and divide each other proportionally.

So, in our case, the diagonals DB and AC intersect at right angles at point D, and they divide each other proportionally. From triangle ADB, we know that AD/BD = AB/BD. Therefore, we can conclude that the side length AD is proportional to the side length DC.

Using this information, we can set up another equation:
AD/DC = AB/CB
2/8 = 3/y
1/4 = 3/y

Now, we have three equations:
x/BC = x/3 [equation 1]
2/x = 3/x [equation 2]
1/4 = 3/y [equation 3]

To solve for x and y, we can simplify equation 1 and 2, and solve the system of equations formed by equation 1, equation 2, and equation 3 simultaneously. However, from the given information, we cannot determine the exact values of x and y without additional constraints or measurements.

So, the equation 3/y = x/x = 2/x is not correct based on the given information in the problem.