How many grams of CuSO4 . 5H2O are needed to prepare 100ml of a 0.10M solution? Remember to change the given volume to liters and take the moles and convert them to grams via the molar mass to get grams of CuSO4 . 5H2O
To determine the number of grams of CuSO4 . 5H2O needed to prepare a 0.10M solution, we need to follow these steps:
Step 1: Convert the given volume from milliliters (ml) to liters (L).
100 ml = 100/1000 = 0.1 L
Step 2: Use the formula to calculate the moles of CuSO4 . 5H2O:
Moles = Molarity x Volume (in liters)
Moles = 0.10 mol/L x 0.1 L = 0.01 mol
Step 3: Calculate the molar mass of CuSO4 . 5H2O.
Cu: 1 atom x 63.5 g/mol = 63.5 g/mol
S: 1 atom x 32.1 g/mol = 32.1 g/mol
O: 4 atoms x 16.0 g/mol = 64.0 g/mol
H: 10 atoms x 1.0 g/mol = 10.0 g/mol
Total molar mass = 63.5 + 32.1 + 64.0 + 10.0 = 169.6 g/mol
Step 4: Calculate the grams of CuSO4 . 5H2O needed:
Grams = Moles x Molar mass
Grams = 0.01 mol x 169.6 g/mol = 1.696 g
Therefore, you would need 1.696 grams of CuSO4 . 5H2O to prepare 100 ml of a 0.10M solution.
To calculate the number of grams of CuSO4 · 5H2O required to prepare a 0.10M solution, we'll follow these steps:
Step 1: Convert the given volume to liters
We are given the volume of the solution as 100 ml. To convert it to liters, we divide by 1000:
100 ml ÷ 1000 = 0.1 liters
Step 2: Calculate the number of moles of CuSO4 · 5H2O
To find the number of moles, we'll use the equation: Molarity (M) = Moles (mol) / Volume (L)
0.10 M = Moles (mol) / 0.1 L
Moles (mol) = 0.10 M × 0.1 L
Moles (mol) = 0.01 mol
Step 3: Convert moles to grams
To convert moles to grams, we'll use the molar mass of CuSO4 · 5H2O.
The molar mass of CuSO4 is 159.61 g/mol, and the molar mass of H2O is 18.02 g/mol.
Now let's calculate the molar mass of CuSO4 · 5H2O:
Molar mass = (159.61 g/mol) + (5 × 18.02 g/mol)
Molar mass = 159.61 g/mol + 90.10 g/mol
Molar mass = 249.71 g/mol
Finally, we can find the number of grams of CuSO4 · 5H2O:
Grams = Moles (mol) × Molar mass (g/mol)
Grams = 0.01 mol × 249.71 g/mol
Grams = 2.4971 grams
Therefore, you will need 2.4971 grams of CuSO4 · 5H2O to prepare 100 ml of a 0.10 M solution.
Mass=volume*molarity*molmass
= .1*.1*249.6 grans