How many number of gold atom are present in 0.6 gm of 18 carat gold.The 24 carat gold is taken as 100% pure gold.(atomic mass of gold=197a.m.u)
75 %
To determine the number of gold atoms in 0.6 gm of 18 carat gold, we need to follow a few steps:
Step 1: Calculate the molar mass of 18 carat gold.
The purity of 18 carat gold is 75% because 18 carat gold contains 75% gold and 25% other metals. Since the atomic mass of gold is 197 a.m.u, the molar mass of 18 carat gold can be calculated using the following formula:
Molar mass of 18 carat gold = (Atomic mass of gold x Percentage of gold purity) / 100
= (197 a.m.u x 75%) / 100
Step 2: Calculate the number of moles of gold in 0.6 gm of 18 carat gold.
We can use the formula: Moles = Mass / Molar mass.
Since we have the mass (0.6 gm) and the molar mass of 18 carat gold (calculated in Step 1), we can substitute these values into the formula to find the number of moles of gold.
Number of moles of gold = 0.6 gm / Molar mass of 18 carat gold
Step 3: Calculate the Avogadro's number.
Avogadro's number represents the number of atoms or molecules in one mole of any substance. The value of Avogadro's number is approximately 6.022 x 10^23.
Step 4: Calculate the number of gold atoms.
To calculate the number of gold atoms, we need to multiply the number of moles of gold (calculated in Step 2) by Avogadro's number.
Number of gold atoms = Number of moles of gold x Avogadro's number
By following these steps, you can determine the number of gold atoms present in 0.6 gm of 18 carat gold.
18 ¡Á A = 24 ¡Á 100
A = 75
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