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block is launched by compressing a spring of constant k=200N/m a distance of 15cm. The spring is mounted horizontally, and the surface directly under it is frictionless. But beyond the equilibrium position of the spring end, the surface has coefficient of friction equal to 0.27 . This frictional surface extends 85cm , followed by a frictionless curved ris
Why did the block become a track star? Because it made a spring-loaded jump!
I'm sorry, but your question seems to be incomplete. Could you please provide the rest of your question?
To solve this problem, let's break it down step by step:
Step 1: Find the potential energy stored in the compressed spring.
The potential energy stored in a spring is given by the formula: U = (1/2) k x^2, where U is the potential energy, k is the spring constant, and x is the displacement of the spring from its equilibrium position.
In this case, the spring constant (k) is given as 200N/m and the displacement (x) is 15cm or 0.15m. Plugging these values into the formula, we can calculate the potential energy stored in the spring.
U = (1/2) * 200N/m * (0.15m)^2
U = 4.5J
Step 2: Determine the maximum kinetic energy of the block.
Since the spring is initially compressed and then released, all the potential energy will convert into kinetic energy when the block is at the maximum displacement.
Therefore, the maximum kinetic energy (K) is equal to the potential energy stored in the spring.
K = 4.5J
Step 3: Calculate the maximum speed of the block.
The kinetic energy of an object is given by the formula: K = (1/2) m v^2, where K is the kinetic energy, m is the mass of the object, and v is its velocity.
In order to find the maximum speed, we can rearrange this formula to solve for v:
v = √(2K / m)
The mass (m) of the block is not given in the question, so it cannot be determined at this point. We'll need this information to proceed further.
Can you provide the mass of the block?