1. Which ordered pair is not a solution of y = –12x – 3?
(–3, 33)
(8, –98)
(–9, 105)
(3, –39)*
2. Find three solutions of the equation.
y = 2x – 6
(–2, –10), (1, –4), (2, –1)
(–2, –10), (1, –4), (0, –6)*
(0, –6), (3, –2), (–2, –10)
(1, –4), (0, –6), (–1, –9)
3. Which pair of points has a positive slope?
(–2, 9), (1, –9)*
(–2, 5), (2, –11)
(–2, –15), (4, 21)
(–2, 13), (1, –11
4. The ordered pairs (2, –21) and (5, –45) are solutions to which of the following equations?
y = –8x – 5
y = –8x + 5
y = 8x – 5
y = 8x+ 5*
5. Which is a rule that describes the translation of a point from (–5, 4) to (–1, 2)?
(x, y) (x – 4, y – 2)
(x, y) (x + 4, y – 2)*
(x, y) (x + 4, y + 2)
(x, y) (x – 4, y + 2)
6. ΔJKL has vertices J(10, 5), K(2, 8), and L(4, 9). It is translated right 5 units and up 4 units. What are the
coordinates of J’, K’, and L’?
J'(15, 9), K'(12, 7), L'(9, 13)
J'(15, 9), K'(7, 12), L'(9, 13)
J'(14, 10), K'(6, 13), L'(10, 12)*
J'(15, 5), K'(7, 8), L'(9, 9)
7. The point M(x, y) is reflected over the x-axis. Use arrow notation to describe the original point and its
reflection.
(x, y) (x, y)*
(x, y) (–x, y)
(x, y) (–x, –y)
(x, y) (x, –y)
WHAT that was so not helpful?!
1. To determine which ordered pair is not a solution of y = -12x - 3, we substitute the x and y values of each pair into the equation and check if the equation holds true. The ordered pair (3, -39) is not a solution of y = -12x - 3 because when we substitute x = 3 and y = -39 into the equation, we get -39 = -12(3) - 3, which simplifies to -39 = -36 - 3, and this is not true.
2. To find three solutions of the equation y = 2x - 6, we can choose any three different x values, substitute them into the equation to find the corresponding y values. The three solutions are (-2, -10), (1, -4), and (0, -6).
3. To determine which pair of points has a positive slope, we can calculate the slope of the line passing through each pair of points. The slope is calculated using the formula (y2 - y1)/(x2 - x1). For the pair of points (-2, 9), (1, -9), the slope is (-9 - 9)/(1 - (-2)) = -18/3 = -6, which is negative. For the pair of points (-2, 5), (2, -11), the slope is (-11 - 5)/(2 - (-2)) = -16/4 = -4, which is negative. For the pair of points (-2, -15), (4, 21), the slope is (21 - (-15))/(4 - (-2)) = 36/6 = 6, which is positive. For the pair of points (-2, 13), (1, -11), the slope is (-11 - 13)/(1 - (-2)) = -24/3 = -8, which is negative. Therefore, the pair of points (–2, 9), (1, –9) has a positive slope.
4. To determine which equation the ordered pairs (2, -21) and (5, -45) are solutions to, we can substitute the x and y values of each pair into each equation and check if the equation holds true. When we substitute x = 2 and y = -21 into the equation y = 8x + 5, we get -21 = 8(2) + 5, which simplifies to -21 = 16 + 5, and this is not true. When we substitute x = 5 and y = -45 into the equation y = 8x + 5, we get -45 = 8(5) + 5, which simplifies to -45 = 40 + 5, and this is not true. Similarly, when we substitute x = 2 and y = -21 into the equation y = -8x + 5, we get -21 = -8(2) + 5, which simplifies to -21 = -16 + 5, and this is not true. However, when we substitute x = 5 and y = -45 into the equation y = -8x + 5, we get -45 = -8(5) + 5, which simplifies -45 = -40 + 5, and this is true. Therefore, the ordered pairs (2, -21) and (5, -45) are solutions to the equation y = -8x + 5.
5. To find the rule that describes the translation of a point from (-5, 4) to (-1, 2), we need to determine how the x and y coordinates change. By comparing the original point (-5, 4) with the translated point (-1, 2), we can see that the x-coordinate increases by 4 (from -5 to -1) and the y-coordinate decreases by 2 (from 4 to 2). Therefore, the rule that describes the translation is (x, y) -> (x + 4, y - 2).
6. To find the coordinates of J', K', and L' after the translation of ΔJKL right 5 units and up 4 units, we need to add 5 to the x-coordinates and 4 to the y-coordinates of the original vertices. The coordinates of J' would be (10 + 5, 5 + 4) = (15, 9), the coordinates of K' would be (2 + 5, 8 + 4) = (7, 12), and the coordinates of L' would be (4 + 5, 9 + 4) = (9, 13). Therefore, the coordinates of J', K', and L' are (15, 9), (7, 12), and (9, 13).
7. When a point M(x, y) is reflected over the x-axis, the y-coordinate of the point changes sign while the x-coordinate remains the same. Therefore, the reflection of the point M(x, y) is (-x, y). The original point is (x, y) and its reflection is (-x, y).
yes
yes
I did not answer your question the first time you posted it, since it looks like an obvious "homework dump"
The first 4 questions simply require that you sub in the values and test.
#5, what happened to the x and to the y value of the original point?
-looks like 4 was added to the x, and 2 subtracted from the y
Now, which of the choices says that ?
#6 , take point j(10,5) . now add 5 to the x and 4 to the y. What do you get?
do that to the other points.
#7
suggestion:
take any point you feel like and plot it.
Now reflect it in the x-axis. What are the new coordinates?
Which choice matches that???