Estimate the pressure that is exerted on the ground by an average female.

In runners?
and then
In "high heels"?

How much does the average female weigh? Are you talking about pressure standing or on the ball of the foot or the heel while walking/running?

Simply standing. 71.1kg.

To estimate the pressure exerted on the ground by an average female, we need to consider the weight distribution and the contact area between her feet and the ground.

In runners:
1. Determine the average weight of an adult female. Let's assume it is 140 pounds (63.5 kilograms).
2. Convert the weight to Newtons by multiplying it by the gravitational acceleration. The gravitational acceleration is approximately 9.8 m/s^2. So, 140 pounds is approximately 633 Newtons.
3. Estimate the contact area of the foot in square meters. Assuming an average foot contact area of 50 square centimeters (0.005 square meters).
4. Calculate the pressure by dividing the weight (in Newtons) by the contact area (in square meters). Thus, the pressure exerted on the ground by an average female in runners would be approximately 633 N / 0.005 m^2 = 126,600 Pascal (Pa).

Now, let's consider the pressure when wearing "high heels." Please note that this is a rough estimate, as the actual weight distribution and heel design vary significantly based on individual factors and shoes.

In "high heels":
1. Assume the weight distribution is similar to that in runners.
2. Estimate the contact area of the heel in square centimeters. Let's assume the heel area is approximately 2 square centimeters (0.0002 square meters).
3. Calculate the pressure using the same weight and formula as before. Thus, the pressure exerted on the ground by an average female in "high heels" would be approximately 633 N / 0.0002 m^2 = 3,165,000 Pa.

Remember, these calculations are based on rough estimates and may vary depending on factors such as body weight, shoe design, posture, and walking style.