four ribbons measuring 4m,18m,22m and 26m respectively are to be cut into piece of equal length.

Question

four ribbons measuring 4m,18m,22m and 26m respectively are to be cut into piece of equal length.

1)find the least no. of piece tat can be obtained?
2)what is the length of each piece?

Answer 1

Maya have three ribbons measuring 28cm,,70cm,126 Maya wants to cut all the ribbons with the same length without any remaining . Calculate the length in cm of the longest ribbon can be cut off and the number of ribbons obtained

Answer 2

we find h.c.f in all four no. then we get h.c.f=2

then we divide all four no. by h.c.f
then we get 7,9,11,13.w add together these no.

Answer 3

1) Well, if we cut the ribbons into equal lengths, we want to find the greatest common divisor (GCD) of the ribbon lengths. Let me use my math skills to calculate it... beep boop beep Ah, the GCD of 4m, 18m, 22m, and 26m is 2m. So, we can cut the ribbons into pieces that are 2m in length.

2) Now that we know the length of each piece is 2m, you can start measuring and snipping away. Just be careful not to trip over the ribbons and end up tangled like a clown in a circus act!

Answer 4

To find the least number of equal-length pieces that can be obtained from the given ribbons, we need to find the greatest common divisor (GCD) of the lengths of all the ribbons. The GCD will be the length of each piece.

1) To find the least number of pieces, we need to calculate the GCD of the given ribbon lengths. Here is the step-by-step process:
- Start by finding the GCD of the first two ribbons: GCD(4, 18) = 2.
- Next, find the GCD of the previous result and the next ribbon: GCD(2, 22) = 2.
- Finally, find the GCD of the previous result and the last ribbon: GCD(2, 26) = 2.
Therefore, the least number of pieces that can be obtained is 2.

2) Now, to find the length of each piece, we need to divide the length of any ribbon by the number of pieces. Since we found that there are 2 pieces, we can choose any of the ribbon lengths to calculate the length of each piece. Let's choose the first ribbon with a length of 4m.
The length of each piece will be 4m divided by 2 pieces, which equals 2m.
Therefore, the length of each piece is 2m.

four ribbons measuring 4m,18m,22m and 26m respectively are to be cut into piece of equal length.

Maya have three ribbons measuring 28cm,,70cm,126 Maya wants to cut all the ribbons with the same length without any remaining . Calculate the length in cm of the longest ribbon can be cut off and the number of ribbons obtained

we find h.c.f in all four no. then we get h.c.f=2

1) Well, if we cut the ribbons into equal lengths, we want to find the greatest common divisor (GCD) of the ribbon lengths. Let me use my math skills to calculate it... *beep boop beep* Ah, the GCD of 4m, 18m, 22m, and 26m is 2m. So, we can cut the ribbons into pieces that are 2m in length.

To find the least number of equal-length pieces that can be obtained from the given ribbons, we need to find the greatest common divisor (GCD) of the lengths of all the ribbons. The GCD will be the length of each piece.

1) Well, if we cut the ribbons into equal lengths, we want to find the greatest common divisor (GCD) of the ribbon lengths. Let me use my math skills to calculate it... beep boop beep Ah, the GCD of 4m, 18m, 22m, and 26m is 2m. So, we can cut the ribbons into pieces that are 2m in length.