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Bacteria can multiply at an alarming rate when each bacteria splits into two new cells, thus doubling. If we start with only bacteria which can double every hour, how many bacteria will we have by the end of the day?

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  1. A number was not specified as the starting amount, so I am assuming the starting number will be 1.

    You would use a formula like:
    y=a(1+r)^x

    a = the initial amount before the growth begins
    r = growth rate
    x = the number of intervals
    y= end result

    r=1 since the rate is only doubling.
    x=24 since there are 24 hours in a day

    y=1(1+1.00)^24

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  2. Your answer is wrong and l did not understand what you write

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  3. I believe the right way to solve for this should be.

    A= y * 2^r (considering the rate is doubling, that is what the 2 is there for)

    A= ending value. (total number of bacteria at the end of 24 hrs)
    y= starting value (can be 1 bacteria, can be 10, depends on the experiment)
    2=doubling
    r= rate or interval (24 hours/one day)

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