CaCO3 ----------> CaO + CO2
When 45 grams of calcium carbonate decomposes, how many grams of calcium oxide are produced?
25.2
mols CaCO3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols CaCO3 to mols CaO.
Now convert mols CaO to grams CaO with g = mols x molar mass = ?
To find the mass of calcium oxide produced in the reaction, we need to calculate the molar masses of calcium carbonate (CaCO3) and calcium oxide (CaO), and then use stoichiometry to relate the two substances.
The molar mass of CaCO3 can be calculated as:
Molar mass of Ca = 40.08 g/mol
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of CaCO3 = (40.08 g/mol) + (12.01 g/mol) + (3 * 16.00 g/mol)
= 100.09 g/mol
The stoichiometric ratio between CaCO3 and CaO is 1:1, meaning for every 1 mole of CaCO3, 1 mole of CaO is produced.
Now, let's calculate the number of moles of CaCO3:
Number of moles = Given mass / Molar mass
Number of moles = 45 g / 100.09 g/mol
≈ 0.4498 mol
Since the stoichiometric ratio is 1:1, the number of moles of CaO produced will also be 0.4498 mol.
Finally, let's calculate the mass of CaO produced:
Mass = Number of moles * Molar mass
Mass = 0.4498 mol * 56.08 g/mol (molar mass of CaO)
= 25.20 g
Therefore, when 45 grams of calcium carbonate decomposes, approximately 25.20 grams of calcium oxide are produced.
To find the number of grams of calcium oxide produced when 45 grams of calcium carbonate decomposes, we need to use the given balanced chemical equation:
CaCO3 ----------> CaO + CO2
From the equation, we can see that 1 mole of calcium carbonate (CaCO3) decomposes to form 1 mole of calcium oxide (CaO). The molar mass of CaCO3 is approximately 100.09 g/mol, and the molar mass of CaO is approximately 56.08 g/mol.
Now, we can use the given mass of calcium carbonate to calculate the number of moles. To do this, we use the formula:
moles = mass / molar mass
moles of CaCO3 = 45 g / 100.09 g/mol ≈ 0.4499 mol
Since the mole ratio between CaCO3 and CaO is 1:1, we can conclude that 0.4499 moles of calcium carbonate will produce the same amount of moles of calcium oxide.
Finally, we can calculate the mass of calcium oxide produced using the formula:
mass = moles × molar mass
mass of CaO = 0.4499 mol × 56.08 g/mol ≈ 25.2 g
Therefore, when 45 grams of calcium carbonate decomposes, approximately 25.2 grams of calcium oxide are produced.