A 40-kg box is being pushed along a horizontal smooth surface. The pushing force is 15 N directed at an angle of 15° below the horizontal. What is the magnitude of the acceleration (in m/s2) of the crate?

Question

A 40-kg box is being pushed along a horizontal smooth surface. The pushing force is 15 N directed at an angle of 15° below the horizontal. What is the magnitude of the acceleration (in m/s2) of the crate?

Answer 1

a = Fx/M = 15*Cos15/M

Answer 2

To find the magnitude of the acceleration of the crate, you can use Newton's second law of motion, which states that the acceleration is equal to the net force divided by the mass of the object.

First, determine the horizontal component of the force. Use the angle given and the trigonometric function cosine to calculate it:

Horizontal component of force = 15 N * cos(15°)

Next, determine the net force acting on the crate. Since the surface is horizontal and smooth, there is no vertical force. Therefore, the only force acting on the crate is the horizontal component of the applied force:

Net force = horizontal component of force

Finally, calculate the acceleration by dividing the net force by the mass of the crate:

Acceleration = Net force / Mass

Substituting the values:
Acceleration = (15 N * cos(15°)) / 40 kg

Calculating the magnitude of acceleration will give you the final answer.

Answer 3

To determine the magnitude of the acceleration of the crate, we need to apply Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

First, we need to split the pushing force into horizontal and vertical components. The magnitude of the horizontal component can be calculated using trigonometry:

Horizontal Component = Pushing Force * cos(angle)
= 15 N * cos(15°)

Next, we can calculate the acceleration using the horizontal component of the net force:

Acceleration = Net Force / Mass

Since there is no vertical component of the force or acceleration due to the smooth surface, we only need to consider the horizontal component of the force.

Finally, let's calculate the magnitude of the acceleration:

Acceleration = 15 N * cos(15°) / 40 kg

Evaluating the expression, we can find the numerical value of the acceleration.

A 40-kg box is being pushed along a horizontal smooth surface. The pushing force is 15 N directed at an angle of 15° below the horizontal. What is the magnitude of the acceleration (in m/s2) of the crate?

.36

a = Fx/M = 15*Cos15/M

To find the magnitude of the acceleration of the crate, you can use Newton's second law of motion, which states that the acceleration is equal to the net force divided by the mass of the object.

To determine the magnitude of the acceleration of the crate, we need to apply Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.