the middle wire carries 2A, and the bottom wire carries 3A.
2A (6 points possible)
What is the magnitude of the force per unit length on the TOP wire in N/m?
1000 - incorrect
1000
What is the direction of the force on the TOP wire?
left right up up - incorrect down into page out of page
To find the magnitude of the force per unit length on the top wire, we can use Ampere's law. Ampere's law states that the magnetic field (B) around a closed loop is proportional to the current (I) passing through the loop.
The equation for Ampere's law is:
B * L = μ0 * I
where B is the magnetic field, L is the length of the loop, μ0 is the permeability of free space (constant value), and I is the current.
In this case, we are given that the middle wire carries a current of 2A. The force between two parallel wires can be calculated using the equation:
F = (μ0 * I1 * I2 * L) / (2π * d)
where F is the force, μ0 is the permeability of free space, I1 and I2 are the currents in the two wires, L is the length of the wires, and d is the distance between the wires.
Since we are only looking for the magnitude of the force per unit length on the top wire, we can simplify the equation by dividing both sides by the length of the top wire. Let's call the length of the top wire "L".
F/L = (μ0 * I1 * I2) / (2π * d)
Substituting the given values:
I1 = 2A (current in the middle wire)
I2 = 3A (current in the bottom wire)
The force per unit length on the top wire can be calculated as:
F/L = (μ0 * 2A * 3A) / (2π * d)
Now, we need to know the value of the distance between the wires (d) to calculate the force per unit length accurately.