How long would it take to bring a 318 kg car moving at 11.2 m/s to a complete stop if a 602.8 N breaking force is applied?
To calculate the time it takes to bring a car to a complete stop, we can use the equation:
force (F) = mass (m) × acceleration (a)
where force is equal to mass multiplied by acceleration. In this case, the force acting on the car is the braking force.
First, let's rearrange the equation to solve for acceleration:
a = F / m
Now we can calculate the acceleration:
a = 602.8 N / 318 kg
a ≈ 1.894 m/s²
Since the car is initially moving at 11.2 m/s and we need to bring it to a complete stop, the final velocity (vf) is 0 m/s.
To calculate the time it takes to stop the car, we can use the equation:
vf = vi + at
where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.
In this case, the initial velocity is 11.2 m/s, final velocity is 0 m/s, and acceleration is -1.894 m/s² (negative because it acts in the opposite direction of motion).
Rearranging the equation, we have:
t = (vf - vi) / a
t = (0 - 11.2 m/s) / (-1.894 m/s²)
Calculating the time:
t ≈ 5.9 seconds
So, it would take approximately 5.9 seconds to bring the 318 kg car moving at 11.2 m/s to a complete stop if a 602.8 N braking force is applied.