Balance the given chemical equation using whole-number coefficients.
?D2(g)+?O2(g)→?D2O(l)
Enter the coefficients in order separated by commas (e.g., 1,3,2, where 1 indicates the lack of a coefficient).
2D2 + 1O2 --> 2D2O
To balance the chemical equation, we need to ensure that the number of atoms of each element is equal on both sides of the equation. Let's break down the equation and count the number of atoms for each element:
Starting with the reactants:
D: There are 2 atoms of D in D2(g).
O: There are 2 atoms of O in O2(g).
Now, let's look at the products:
D: There are 2 atoms of D in D2O(l).
O: There is 1 atom of O in D2O(l).
Since we have 2 atoms of O in the reactants and only 1 atom of O in the product, we need to balance the equation by adding a coefficient for O2(g) and D2O(l).
To balance the equation, we can follow these steps:
1. Start by balancing elements that appear in only one reactant and one product. In this case, we have D2O on the product side.
D2(g) + ?O2(g) → 1D2O(l)
2. Next, balance elements that appear in multiple compounds, starting with the most complex molecules (D2O in this case). In the product side, we currently have 1 atom of O. Since we need 2 atoms of O, we can multiply the coefficient of D2O by 2:
D2(g) + ?O2(g) → 2D2O(l)
3. Now, check if we have balanced all elements. We only have D left to balance. Since we have 2 atoms of D on the reactant side and 4 atoms of D on the product side, we can balance D by multiplying the coefficient of D2(g) by 2:
2D2(g) + ?O2(g) → 2D2O(l)
By balancing the equation, we end up with:
2D2(g) + ?O2(g) → 2D2O(l)
In this case, we have balanced the equation by using the coefficients 2, 1, and 2 for D2(g), O2(g), and D2O(l) respectively.
To balance the chemical equation D2(g) + O2(g) → D2O(l), follow these steps:
1. Start by counting the number of atoms for each element on both sides of the equation.
On the left side (reactants):
- D: 2 atoms
- O: 2 atoms
On the right side (products):
- D: 2 atoms
- O: 1 atom
2. Begin balancing with the most complex molecule or the one with the highest number of atoms. In this case, it's D2O.
Place the coefficient of 2 in front of D2O.
The equation becomes:
D2(g) + O2(g) → 2D2O(l)
3. Now check the number of atoms for each element again.
On the left side (reactants):
- D: 2 atoms
- O: 2 atoms
On the right side (products):
- D: 4 atoms
- O: 2 atoms
4. Since there are more hydrogen (D) atoms on the right side, we need to balance them.
Place the coefficient of 2 in front of D2.
The equation becomes:
2D2(g) + O2(g) → 2D2O(l)
5. Check the atoms again.
On the left side (reactants):
- D: 4 atoms
- O: 2 atoms
On the right side (products):
- D: 4 atoms
- O: 2 atoms
6. The equation is now balanced, with equal numbers of atoms on both sides.
The balanced chemical equation is:
2D2(g) + O2(g) → 2D2O(l)