A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn.
A) What is the probability of selecting a purple marble and then a white marble? B) What is the probability of selecting two white marbles? C) Is there a greater chance of selecting two white marbles in a row or two purple marbles in a row? Show your work.
PLZ HURRY UP URGENT I HAVE TO SUBMIT BY 8:30
in general, the probability of some event
= number of times that event can happen/total number of possible outcomes
so ...
you have 2 white and 7 purple
prob of purple = 7/9
then
prob of white = 2/8 , there are only 8 left since you drew one already.
prob(purple, then white) = (7/9)(2/4) = 7/36
prob(2 whites) = (2/9)(1/8) = 1/36
prob(2 purples) = 7/9(6/8) = 7/12
and of course 7/12 > 1/36
clearly , since you had more purples than whites, the chances of getting purples would be greater than the chances of getting whites.
prob of getting the 5 on the spin = 1/6
prob of getting a pair = 6/36 =1/6
So she has the same chance of winning at either games, makes no difference.
ANSWER THE DANG QUESTION US KIDS ARE TRYING TO PASS OUR GRADE OK
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
A. 7/9 * 2/(9-1) = ?
B. 2/9 * (2-1)/9-1) = ?
C. Use similar processes for this question.
The person who originally asked this question is a sophomore now lol
Thou Shalt haveth no other Gods before Me
Read the Bible idiot that's not a comandment