How do i find the 12th term of the sequence
36,18,9....
using a formula
http://www.jiskha.com/display.cgi?id=1428959236
i cant figure it out
Use the formula that bobpursley posted.
Post your attempts at applying that formula to this problem. If you post them here, probably a math tutor can help you.
t12=36(1/3)^11
36(1/2048)
=0.017578125
right or wrong?
To find the 12th term of the sequence 36, 18, 9..., we first need to identify the pattern in the sequence. In this case, we can observe that each term is half of the previous term in the sequence.
To find the nth term of a sequence where each term is calculated by multiplying or dividing by the same value, we can use the formula:
Tn = a * r^(n-1)
Where Tn represents the nth term, a is the first term in the sequence, r is the common ratio, and n is the position of the term in the sequence.
In this case, the first term (a) is 36 and the common ratio (r) is 1/2.
Now, let's plug in the values into the formula to find the 12th term (T12):
T12 = 36 * (1/2)^(12-1)
T12 = 36 * (1/2)^11
T12 = 36 * (1/2048)
T12 = 0.017578125
Therefore, the 12th term of the sequence 36, 18, 9... is approximately 0.0176.