Chemistry

Identify the correct statement for the following reaction:

Br2 (l) → Br2 (g) ΔH° = 30.9 kJ ΔS° = 93.2 J/K


A) The reaction is always spontaneous.

B) The reaction is never spontaneous.

C) The reaction is at equilibrium; therefore, ΔG° = 0.

D) The reaction could be spontaneous at high temperatures.

E) The reaction could be spontaneous at low temperature.

  1. 👍
  2. 👎
  3. 👁
  1. Used the following equation and plug in a couple of variables for T and see what you get.

    ΔG=ΔH−TΔS

    Remember, if ΔG is negative then the reaction is spontaneous, if positive, than the reaction is not spontaneous, and if equal to 0 is at equilibrium.

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. chemistry help

    For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants? 2Na(s)+Br2(g) ---->2NaBr(s) 1. 2mol Na, 2mol Br2 2. 1.8mol Na, 1.4mol Br2 3. 2.5mol Na, 1mol Br2 4. 12.6mol Na, 6.9 mol Br2

  2. Chemimstry

    Consider this reaction involving an unknown element X. F2+2XBr = Br2+2XF When 5.200 g of XBr reacts, 2.896 g of Br2 is produced. Calculate the molar mass of XBr in g/mols? What is the element symbol for X? I know that I need to

  3. chemistry

    Nitrosyl bromide decomposes according to the following equation. 2NOBr (g)(equilibrium arrow) 2NO (g) + Br2 (g) A sample of NOBr (0.64 mol) was placed in a 1.00-L flask containing no NO or Br2. At equilibrium the flask contained

  4. Chemistry

    At 1285°C, the equilibrium constant for the reaction Br2 (gas) 2Br (gas) is Keq= 1.04 X 10^ -3 A 0.200-L vessel containing an equilibrium mixture of gases has 0.245 g. Br2 (gas) in it. What is the mass of Br (gas) in the vessel?

  1. Chemistry

    For the following reaction, Kp = 3.5 104 at 1495 K. H2(g) + Br2(g) 2 HBr(g) What is the value of Kp for the following reactions at 1495 K? (a) HBr(g) 1/2 H2(g) + 1/2 Br2(g) (b) 2 HBr(g) H2(g) + Br2(g) (c) 1/2 H2(g) + 1/2 Br2(g)

  2. chemistry

    write the equations for the substitution reaction of methene with bromine under the following conditions. a) reaction in the presence of sunlight CH4+Br2 sunlight=? b) reaction in the absence of sunlight CH4+Br2 =?

  3. chemistry:)

    The bond enthalpy of the Br–Cl bond is equal to DH° for the reaction BrCl(g)-> Br(g) + Cl(g). Use the following data to find the bond enthalpy of the Br–Cl bond. Br2(l)--->Br2(g) ÄH=30.91 KJ/mol Br2(g)--->2Br2(g) ÄH=192.9

  4. Chemistry

    What is the enthalpy change (in kJ/mol) for the following process? Na+(g) + Br-(g) --> NaBr (s) Hint: use the Born-Haber cycle Note: the reference state for Br2 is Br2(l) not Br2(g) Data (in kJ/mol): enthalpy of sublimation of

  1. Chemistry

    If the reaction H2 + Br2 2HBr has a rate law that can be described by k[H2][Br2]1/2, which series of reactions is a possible mechanism for the reaction? a. Br2 2Br (fast) Br + H2 HBr + H (slow) HBr + H + Br → 2HBr (fast) b.

  2. chemistry

    A studen is asket to calculate the amount of heat involved in changing 10.0 g of liquid bomine at room temperature (22.5 C) to vapor at 59.0 C. To do this, one must know specific heat (0.474 J/g*C), boiling point (59 C), and heat

  3. Chem - Redox rxn

    Just wanna make sure, if i did it correct or not. Cl2 + 2NaBr --> Br2 + 2NaCl (0)---(+1)--(-1)---(0)------(+1)(-1) So Cl2 loss = oxidation Br2 Gain = Reduction Am I correct ? Thanks

  4. science

    What is ∆H0 for this reaction? Br2(g) → Br2(l) (∆Hf0 Br2(g) = 30.91 kJ/mol) 1.546 × 101 kJ –1.546 × 101 kJ 3.091 × 101 kJ –3.091 × 101 kJ

You can view more similar questions or ask a new question.