three 20 kilo ohms Resistors R1, R2, and R3 are in Series across an applied voltage of 120 V. What is the voltage drop across each resistor.
Rt = R1+R2+R3 = 20k + 20k + 20k = 60k Ohms. = Total resistance.
I = E/Rt = 120/60k = 2 mA(milliamps).
V1 = V2 = V3 = I*R1 = 2 * 20k = 40 Volts
Therefore, the voltage across each resistor is 40 Volts.
Resistance across resistors in series
= R1+R2+R3
Voltage across each resistor is proportional to the fraction of each over the total.
For example,
resistors R1=2,R2=1,R3=3, ohms are connected in series and subject to a voltage of 12 volts,
Resistance of resistors in series
R=R1+R2+R3=2+1+3=6
voltage drops
V1=(R1/R)*12=(2/6)*12=4 volts
V2=(R2/R)*12=(1/6)*12=2 volts
V3=(R3/R)*12=(3/6)*12=6 volts
Check: total = 4+2+6=12 volts, ok.
Thanks.. :)
To find the voltage drop across each resistor in a series circuit, we need to divide the total voltage by the total resistance.
In this case, we have three resistors in series, each with a resistance of 20 kilo ohms. The total resistance in a series circuit is found by adding the resistances of each resistor:
Total Resistance (R_total) = R1 + R2 + R3 = 20kΩ + 20kΩ + 20kΩ = 60kΩ
Now, we can use Ohm's Law to find the voltage drop across each resistor. Ohm's Law states that the voltage (V) is equal to the current (I) multiplied by the resistance (R):
V = I * R
In a series circuit, the current passing through each resistor is the same. Therefore, we can use the total voltage (120 V) and the total resistance (60kΩ) to find the current (I):
I = V / R_total = 120 V / 60kΩ = 0.002 A
Now, we can find the voltage drop across each resistor by multiplying the current (0.002 A) by the resistance of each resistor:
Voltage drop across R1 = I * R1 = 0.002 A * 20kΩ = 40 V
Voltage drop across R2 = I * R2 = 0.002 A * 20kΩ = 40 V
Voltage drop across R3 = I * R3 = 0.002 A * 20kΩ = 40 V
Therefore, the voltage drop across each resistor is 40 volts.