Find the ordered pair(s) that satisfies both f(x)=3/2x+1 and g(x)=-1/2x^2+2x+2.

so you want:

(3/2)x + 1 = (-1/2)x^2 + 2x + 2
times 2
3x + 2 = -x^2 + 4x + 4
x^2 - x - 2 = 0
(x-2)(x+1) = 0
take over