Graph the relation. Find the domain and range.

{(-1,1/2),(-1/2,-1),(3/2,0),(2,3/2)}

To graph the relation, we plot the given points on a coordinate plane.

The points given in the relation are:

(-1, 1/2)
(-1/2, -1)
(3/2, 0)
(2, 3/2)

Plotting these points on the coordinate plane, we get:

\[
\begin{array}{c|c}
x & y \\
\hline
-1 & \frac{1}{2} \\
-\frac{1}{2} & -1 \\
\frac{3}{2} & 0 \\
2 & \frac{3}{2} \\
\end{array}
\]

The graph of the relation is as follows:

```
|
3/2 |
|
--------|---------
|
-1/2 |
|
--------|---------
|
-1 |
|
--------|---------
|
-3/2 |
|
```

Next, let's find the domain and range:

The domain is the set of all x-values in the relation. By looking at the graph, we can see that the x-values range from -1 to 2, inclusive. So, the domain is (-1, 2].

The range is the set of all y-values in the relation. By looking at the graph, we can see that the y-values range from -3/2 to 3/2, inclusive. So, the range is [-3/2, 3/2].

To graph the relation, plot the given points on a coordinate plane:

Point (-1, 1/2) is located at (-1, 1/2).
Point (-1/2, -1) is located at (-1/2, -1).
Point (3/2, 0) is located at (3/2, 0).
Point (2, 3/2) is located at (2, 3/2).

Now, connect these points with a curve or line, depending on the nature of the relation.

To find the domain, identify all the x-values from the given points. The domain is the set of all possible x-values in the relation.

In this case, the domain is {-1, -1/2, 3/2, 2}.

To find the range, identify all the y-values from the given points. The range is the set of all possible y-values in the relation.

In this case, the range is {1/2, -1, 0, 3/2}.

So, the graph of the relation is as plotted above, and the domain is {-1, -1/2, 3/2, 2}, while the range is {1/2, -1, 0, 3/2}.

the domain is the set of all first elements (the x's) and the range is the set of all the 2nd elements (the y's)

I am sure you can plot those points