Can someone please help me with these two problems?
1).12 < 12 + 4x < 0
2). 12 – x > 15 or 7x – 13 > 1
I'm working with compound equalities and have no clue on where to start.
divide it up into two problems
12 <12+ 4x
4 x >0
or
x >0
and
12+4x <0
4 x < -12
x < - 3
so x is either left of -3 or right of 0 on a number line
12 - x > 15
-x > 3
multiply both sides by -1 BUT change direction of arrow when changing signs
x < - 3 (LOL - again)
7 x - 13 > 1
7 x > 14
x > 2
so x is left of -3 or right of +2
Ok thank you so much Damon!!!
You are welcome.
How could I graph the two problems?
Well, I told you
number line
eg
so x is left of -3 or right of +2