Find the reference angle for the given angle. Show your work.
-404°
my answer is 44 degree , But i don't know how to put my work together..
theta +/- n (360) = theta
so
-404 + 360 = -44
which is indeed 44 degrees below the x axis in quadrant 4
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You could also call it + (360-44) = 316
counterclockwise from the x axis but if you are doing triangles for trig you would use that 44 for a reference angle.
See:
https://www.google.com/search?q=reference+angle+trig+definition&ie=utf-8&oe=utf-8
Thank you !!
To find the reference angle for -404°, we need to consider the angle's position in the coordinate plane.
The reference angle is the positive acute angle formed between the terminal side of the given angle and the x-axis.
First, let's determine the equivalent positive angle for -404°. We can add 360° to -404°:
-404° + 360° = -44°
So, the equivalent positive angle is -44°.
Next, we need to find the reference angle, which is always positive. It is the acute angle between the terminal side of the angle (in this case, -44°) and the x-axis.
To find the reference angle, we subtract the equivalent positive angle from 180°:
180° - |-44°| = 180° - 44° = 136°
Finally, the reference angle for -404° is 136°.