a 100 gram sample of a metal undergoes a temperature change from 20 C to 50 C Absorbing 1500J of heat

To calculate the specific heat capacity of the metal, we can use the formula:

q = m * c * ΔT

Where:
q = heat absorbed/lost (in Joules)
m = mass of the sample (in grams)
c = specific heat capacity of the metal (in J/g°C)
ΔT = change in temperature (in °C)

In this case, the sample has a mass of 100 grams, the temperature change is from 20°C to 50°C, and the heat absorbed is 1500 J.

Let's substitute the given values into the formula and solve for the specific heat capacity (c):

1500 J = 100 g * c * (50°C - 20°C)

First, let's calculate the difference in temperature:

ΔT = 50°C - 20°C
ΔT = 30°C

Now, let's rearrange the equation to solve for c:

c = 1500 J / (100 g * 30°C)
c = 1500 J / 3000 g°C
c = 0.5 J/g°C

Therefore, the specific heat capacity of the metal is 0.5 J/g°C.

To determine the specific heat capacity of the metal, we can use the formula:

\(Q = mcΔT\)

where:
- \(Q\) is the heat energy absorbed by the metal (in joules)
- \(m\) is the mass of the metal (in grams)
- \(c\) is the specific heat capacity of the metal (in J/g°C)
- \(ΔT\) is the change in temperature (in °C)

In this case, the heat energy absorbed (\(Q\)) is given as 1500J, the mass (\(m\)) is 100 grams, and the change in temperature (\(ΔT\)) is 50°C - 20°C = 30°C.

Now we can rearrange the formula to solve for the specific heat capacity (\(c\)):

\(c = \frac{Q}{mΔT}\)

Plugging in the values we have:

\(c = \frac{1500J}{100g \times 30°C}\)

Now we can calculate:

\(c = \frac{1500J}{3000g°C}\)
\(c = 0.5 J/g°C\)

Therefore, the specific heat capacity of the metal is 0.5 J/g°C.

I don't see a question here.

If the problem asks for the specific heat capacity, then we just use the formula,

Q = mc(T2-T1)
where
Q = heat (J)
m = mass (g)
c = specific heat capacity (J/g-K)
T2 = final temperature (K)
T1 = initial temperature (K)

Substituting,
1500 = 100 * c * (50 - 20)
c = ?

Now solve for c. Hope this helps~ `u`