Chemistry

A solution of hexane in the solvent (CH3)2CO has a mole fraction of CH3(CH2)4CH3 of 0.114. What mass (g) of the solution must be taken if 1690 g of hexane is needed?
Molar Mass (g/mol)
CH3(CH2)4CH3 100.21
(CH3)2CO 58.05

Density (kg/L):
CH3(CH2)4CH3 0.6838
(CH3)2CO 0.7899

Name/Formula:
hexane
CH3(CH2)4CH3
acetone
(CH3)2CO

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asked by Scott
  1. 0.114 = X(hexane)/X(hexane)+X(acetone)
    X(hexane) = 1690 g hexane/100.21
    X(acetone) = grams acetone/58.05
    You have only one unknown. Solve for grams acetone. Then g acetone + 1690 = total grams.Check my thinking. Check my work. Post your work if you need further assistance.

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    posted by DrBob222

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