Physics

Two forces 10 N acting in the direction N 30 east and 15 N acting in the eastern direction, if both forces act at a point, find the magnitude and direction of (a) the resultant force (b) the equilibriant force.

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  1. a. Fr = 10N[60o]CCW + 15N[0o]

    X = 10*Cos60 + 15 = 20 N.
    Y = 10*sin60 = 8.7 N.
    Q1.

    Tan A = Y/X = 8.7/20 = 0.433
    A = 23.4o N. of E.

    Fr = X/Cos A = 20/Cos23.4=21.8 N.[23.4o]
    N. of E. = 23.4o CCW

    b. Equilibrant:
    X = -20
    Y = -8.7
    Q3.

    Tan A = Y/X = -8.7/-20 = 0.433
    A = 23.4o S. of W. = 203.4o CCW.

    Fr = X/Cos A = -20/Cos203.4 = 21.8 N[23.4o S. of W. = 203.4o CCW.

    Note: 23.4o S. of W. is the opposite of
    23.4o N. of E. and their magnitudes are
    equal.

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  2. I need the diagram

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  3. I want a clear solution because you didn't involved N30 from the question above

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  4. I agree with wat she said

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