What is the value of x in the system shown?
y=1/5x+2
y=x-4
I do not know.
Do you mean
y=(1/5)x+2
y=x-4
then
x + 10 = 5 x - 20
x = 30/4 = 15/2 = 7.5
or do you mean
y = 1/(5x) + 2
then
1 + 10 x = 5 x^2 - 20 x
solve quadratic
or do you mean
1/(5x+2) = x-4
1 = (5x+2)(x-4)
1 = 5 x^2 + 18 x - 8
etc
how do you get this ?
x + 10 = 5 x - 20
I said
(1/5) x + 2 = x - 4
multiply everything both sides by 5
x + 10 = 5 x - 20
Thank you for answering =)
You are welcome :)
To find the value of x in this system of equations, we need to solve for x by setting the equations equal to each other.
First, let's set the two equations equal to each other:
1/5x + 2 = x - 4
To eliminate the fractions, we can multiply both sides of the equation by 5 to clear the fraction:
5 * (1/5x + 2) = 5 * (x - 4)
(x/1) + 10 = 5x - 20
Next, let's simplify the equation by distributing the 5 on the left side:
x + 10 = 5x - 20
To isolate the variable x, we will move the x terms to one side of the equation and the constant terms to the other side:
x - 5x = -20 - 10
-4x = -30
To solve for x, we can divide both sides of the equation by -4:
-4x / -4 = -30 / -4
x = 7.5
Therefore, the value of x in the given system of equations is 7.5.