If a .750g sample of magnesium chloride is dissolved in water and then treated with a silver nitrate solution how many grams of silver chloride should be collected?
I don't understand what my first step should be.
The balanced equation is
MgCl2+2AgNO3=2AgCl+Mg (NO3)2
Do I have to convert to moles? Please help.
0.750g of MgCl2*(1 mol/95.211g)=0.007877 mol of MgCl2
*****1 mol of MgCl2=2 moles of AgCl
This is the key and is where your error lies.
0.007877 mol of MgCl2*(2 mol of AgCl/MgCl2)=0.01575 moles of AgCl
0.01575 moles of AgCl*(143.32 g/mol)=2.26g of AgCl
Best
I got the answer 1.125grams.
Please help!
Yes, the first step is typically to convert the mass of magnesium chloride to moles. To do this, you can use the molar mass of magnesium chloride, which is 95.211 g/mol.
To convert grams to moles, divide the mass by the molar mass:
0.750 g MgCl2 / 95.211 g/mol = 0.00787 mol MgCl2
Next, you can use the balanced equation to determine the mole ratio between magnesium chloride and silver chloride. From the equation, we can see that 1 mole of MgCl2 reacts to form 2 moles of AgCl.
Therefore, based on the balanced equation, 0.00787 mol of MgCl2 will produce:
0.00787 mol MgCl2 × 2 mol AgCl / 1 mol MgCl2 = 0.0157 mol AgCl
Finally, to convert moles of silver chloride to grams, you can use the molar mass of silver chloride, which is 143.32 g/mol.
0.0157 mol AgCl × 143.32 g/mol = 2.25 g AgCl
So, you should collect approximately 2.25 grams of silver chloride.
Yes, converting the given mass of magnesium chloride to moles would be the first step in solving this problem.
To convert from grams to moles, you need to use the molar mass of magnesium chloride (MgCl2). The molar mass is calculated by adding up the atomic masses of each element in the compound.
The atomic masses of magnesium (Mg) and chlorine (Cl) are found on the periodic table. The molar mass of magnesium is approximately 24.31 g/mol, and the molar mass of chlorine is approximately 35.45 g/mol. Since there are two chlorine atoms in magnesium chloride, you need to multiply the molar mass of chlorine by 2.
So, the molar mass of magnesium chloride is:
(24.31 g/mol) + (35.45 g/mol * 2) = 95.21 g/mol
To convert the given mass of magnesium chloride to moles, divide the mass by the molar mass:
0.750 g / 95.21 g/mol ≈ 0.00788 mol
Now that you have the number of moles of magnesium chloride, you can use the balanced equation to determine the stoichiometry between magnesium chloride and silver chloride.
According to the balanced equation, 1 mole of magnesium chloride (MgCl2) reacts with 2 moles of silver nitrate (AgNO3) to produce 2 moles of silver chloride (AgCl).
So, for every 1 mole of magnesium chloride, you would expect to form 2 moles of silver chloride.
Since you have 0.00788 mol of magnesium chloride, you can multiply this by the mole ratio to find the moles of silver chloride produced:
0.00788 mol MgCl2 * (2 mol AgCl / 1 mol MgCl2) = 0.01576 mol AgCl
Now, to convert this back to grams, you need to multiply the moles by the molar mass of silver chloride. The molar mass of silver chloride (AgCl) is approximately 143.32 g/mol.
So, the mass of silver chloride collected should be:
0.01576 mol AgCl * 143.32 g/mol ≈ 2.253 g AgCl
Therefore, approximately 2.253 grams of silver chloride should be collected.