The partial pressure of fluorine gas (F2) in a mixture of gases where the total pressure is 1.00 atm is 300. torr. What percent of the mixture is made of fluorine gas

To find the percentage of the mixture that is made of fluorine gas, we need to compare the partial pressure of fluorine gas to the total pressure of the mixture.

First, let's convert the partial pressure of fluorine gas into the same unit as the total pressure. The given partial pressure of fluorine gas is 300 torr. Since 1 atm is equal to 760 torr, we can convert 300 torr to atm by dividing it by 760:

300 torr / 760 torr/atm = 0.3947 atm

Now we can compare the partial pressure of fluorine gas to the total pressure of the mixture:

Percentage of fluorine gas = (Partial pressure of fluorine gas / Total pressure) x 100

Percentage of fluorine gas = (0.3947 atm / 1.00 atm) x 100

Percentage of fluorine gas ≈ 39.47%

Therefore, approximately 39.47% of the mixture is made of fluorine gas.

To find the percent of the mixture made of fluorine gas (F2), we need to convert the partial pressure of F2 to atm and then calculate the percentage.

1. Convert the partial pressure of F2 to atm:
300 torr = 300/760 atm = 0.3947 atm

2. Calculate the percentage:
Percentage = (Partial Pressure of F2 / Total Pressure) * 100
= (0.3947 atm / 1.00 atm) * 100
= 39.47%

Therefore, approximately 39.47% of the mixture is made of fluorine gas (F2).

XF2 = pF2/Ptotal

mole % = X*100 = ?