physics

The figure below shows a clawhammer as it is being used to pull a nail out of a horizontal board. A force of magnitude 130 N is exerted horizontally as shown. (NOTE: Assume that the force the hammer exerts on the nail is parallel to the nail and perpendicular to the position vector from the point of contact. The x-component of this force's lever arm is 5 cm.)

(a) Find the force exerted by the hammer claws on the nail.

(b) Find the force exerted by the surface at the point of contact with the hammer head.

webassign(dot)net/sercp9/8-p-068(dot)gif

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  1. Isn't this just a leaver mechanical advantage issue?

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    bobpursley
  2. Yes. Still need help figuring out the forces exerted though.

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  3. The instructor wants us to use the sum of the torques to figure out the problem.

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  4. The web address is posted below my question if you would like to see the picture. The (dot)=.

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  5. measure the distance from the hand to the fulcrum, and the distance from the fulcrum to the nail.

    Forcehand*distancehandToF=forcenail*distancenailtoF.

    Why is this so? The same amount of work is done on each end. Work=forceapplied*distancemoved thru.

    However, the distance the force moves through is directly proportional to the distance to the handle fulcurm (thnk on that).

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    bobpursley
  6. work=torque*angle displacement

    now proved by similar triangles the angle displacements are the same on the claw, and the handle. Leaving you with my force*distancetofulcrum argument above.

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    bobpursley
  7. Thank you very much. That makes sense. I will apply that reasoning.

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  8. Did you examine the picture? There are angles involved. The nail is at a 30 degree angle in the wood.

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  9. No, didn't see the picture. You take care of that in the torque, sine of the angle between force and the object direction.

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    bobpursley

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