Calculate the molarity (M) of the following solutions:
4.00moles of glucose in 3.00L of glucose solution
5.50g of KOH in 4.00L of KOH solution
5.85g of NaCl in 400.mL of NaCl solution
85g of oxygen react, how many grams of aluminum are required. The molar mass of oxygen is 32.0g/mol and the molar mass of aluminum is 27.0g/mole
To calculate the molarity (M) of a solution, you need to know the number of moles of solute and the volume of the solution. The formula for molarity is:
Molarity (M) = Moles of solute / Volume of solution (in liters)
Let's calculate the molarity of each solution step-by-step:
1. For 4.00 moles of glucose in 3.00 L of glucose solution:
Moles of glucose = 4.00 moles
Volume of glucose solution = 3.00 L
Molarity (M) = Moles of glucose / Volume of glucose solution
Molarity = 4.00 moles / 3.00 L
Molarity = 1.33 M
Therefore, the molarity of the glucose solution is 1.33 M.
2. For 5.50 g of KOH in 4.00 L of KOH solution:
To find the moles of KOH, you need to convert the grams to moles using the molecular weight of KOH.
The molecular weight of KOH is:
K (39.10 g/mol) + O (16.00 g/mol) + H (1.01 g/mol) = 56.11 g/mol
Moles of KOH = 5.50 g / 56.11 g/mol
Next, we need to convert the volume from liters to milliliters:
Volume of KOH solution = 4.00 L = 4000 mL
Molarity (M) = Moles of KOH / Volume of KOH solution (in liters)
Molarity = (5.50 g / 56.11 g/mol) / 4.00 L
Molarity = 0.0246 mol / 4.00 L
Molarity = 0.00615 M
Therefore, the molarity of the KOH solution is 0.00615 M.
3. For 5.85 g of NaCl in 400 mL of NaCl solution:
To find the moles of NaCl, you need to convert the grams to moles using the molecular weight of NaCl.
The molecular weight of NaCl is:
Na (22.99 g/mol) + Cl (35.45 g/mol) = 58.44 g/mol
Moles of NaCl = 5.85 g / 58.44 g/mol
Next, we need to convert the volume from milliliters to liters:
Volume of NaCl solution = 400 mL = 0.400 L
Molarity (M) = Moles of NaCl / Volume of NaCl solution (in liters)
Molarity = (5.85 g / 58.44 g/mol) / 0.400 L
Molarity = 0.100 mol / 0.400 L
Molarity = 0.250 M
Therefore, the molarity of the NaCl solution is 0.250 M.
To calculate the molarity (M) of a solution, you need to know the amount of solute and the volume of the solution in liters. The formula for molarity is:
M = moles of solute / liters of solution
Now let's calculate the molarity for each solution:
1. 4.00 moles of glucose in 3.00 L of glucose solution:
To find the molarity, divide the moles of solute (glucose) by the liters of solution.
M = 4.00 moles / 3.00 L
M = 1.33 M
The molarity of the solution is 1.33 M.
2. 5.50g of KOH in 4.00 L of KOH solution:
First, we need to convert the mass of KOH into moles. To do this, we need the molar mass of KOH, which is the sum of the atomic masses of potassium (K), oxygen (O), and hydrogen (H).
Molar mass of KOH = atomic mass of K + atomic mass of O + atomic mass of H
Molar mass of KOH = 39.10 g/mol + 16.00 g/mol + 1.01 g/mol
Molar mass of KOH = 56.11 g/mol
Next, we can use the formula to calculate the moles of KOH:
moles = mass / molar mass
moles = 5.50 g / 56.11 g/mol
moles = 0.0981 mol
Finally, we can calculate the molarity:
M = moles of solute / liters of solution
M = 0.0981 mol / 4.00 L
M = 0.0245 M
The molarity of the solution is 0.0245 M.
3. 5.85g of NaCl in 400 mL of NaCl solution:
First, we need to convert the volume of the solution from milliliters to liters. There are 1000 mL in 1 L, so:
Volume = 400 mL / 1000
Volume = 0.400 L
Now, we can calculate the moles of NaCl by dividing the mass by the molar mass of NaCl, which is the sum of the atomic masses of sodium (Na) and chlorine (Cl).
Molar mass of NaCl = atomic mass of Na + atomic mass of Cl
Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol
Molar mass of NaCl = 58.44 g/mol
moles = mass / molar mass
moles = 5.85 g / 58.44 g/mol
moles = 0.1 mol
Now we can calculate the molarity:
M = moles of solute / liters of solution
M = 0.1 mol / 0.400 L
M = 0.25 M
The molarity of the solution is 0.25 M.
M = mols/L solution
For those with grams, use mols = grams/molar mass to find mols.