A rectangular piece of construction paper is 11 inches long and 8 inches wide. How could it be cut to make a rectangle that has an area of 32 square inches?
4 by 8
what is 8 inches and 11 inches wide? and how to draw a picture are the area
You would have to cut seven inches.
To find the dimensions of the rectangle with an area of 32 square inches, we can use the formula for the area of a rectangle: Area = Length × Width.
Given that the original piece of construction paper is 11 inches long and 8 inches wide, we need to determine how to cut it to obtain a rectangle with an area of 32 square inches.
First, let's list the possible dimensions of the rectangle with an area of 32 square inches:
1. Length: 1 inch, Width: 32 inches (1 × 32 = 32)
2. Length: 2 inches, Width: 16 inches (2 × 16 = 32)
3. Length: 4 inches, Width: 8 inches (4 × 8 = 32)
4. Length: 8 inches, Width: 4 inches (8 × 4 = 32)
5. Length: 16 inches, Width: 2 inches (16 × 2 = 32)
6. Length: 32 inches, Width: 1 inch (32 × 1 = 32)
These combinations show the different ways the original piece of construction paper could be cut to obtain a rectangle with an area of 32 square inches.