1) When will the dependent variable in the equation y=√x+4-3 equal or exceed to 4?
A) x > or equal to -0.17
B) x > or equal to 45
C) x > or equal to 48
D) x > or equal to 53
2) The function t=√d/16 models the time (t) in seconds that an object has been falling after the object has fallen d feet. When will the time be more than 1 minute?
A) d > or equal to 16 ft
B) d > or equal to 225 ft
C) d > or equal to 3,600 ft
D) d > or equal to 57,600 ft
I do not know how to solve these questions. I am quite confused and help would mean a lot to me. Thank you! If you can only solve one question that is extremely fine. :) I just need help.
#1
√(x+4)-3 >= 4
√(x+4) >= 7
x+4 >= 49
x >= 53
#2
t = √(d/16), so we want (using t in seconds)
√(d/16) > 60
d/16 > 3600
d > 57600
Thank you so much! I really appreciate all your help.
For number one I think the answer should be 45 because Steve added 4 instead of subtracting 4!!!!
Sure, I can help you with these questions!
1) To find when the dependent variable in the equation y=√x+4-3 equals or exceeds 4, you can set up an inequality:
√x+4-3 ≥ 4
Next, isolate the square root term by adding 3 to both sides:
√x+4 ≥ 7
Now, square both sides to eliminate the square root:
(x+4) ≥ 7^2
Simplifying the right side:
x+4 ≥ 49
Finally, subtract 4 from both sides to solve for x:
x ≥ 45
So the correct answer is B) x > or equal to 45.
2) Similarly, to find when the time t in seconds is more than 1 minute, you can set up an inequality:
√d/16 > 60 seconds
To get rid of the square root, square both sides:
(d/16) > (60 seconds)^2
Simplifying:
d/16 > 3600 seconds
Now, multiply both sides by 16 to isolate d:
d > 3600 seconds * 16
d > 57,600 seconds
So the correct answer is D) d > or equal to 57,600 ft.
I hope this helps! Let me know if you have any more questions.