A rescue helicopter is lifting a man (weight = 868 N) from a capsized boat by means of a cable and harness. (a) What is the tension in the cable when the man is given an initial upward acceleration of 1.83 m/s2? (b) What is the tension during the remainder of the rescue when he is pulled upward at a constant velocity?
I found the first tension= 1030.90N, however I am stuck on trying to figure out the other one. Please help!
To find the tension in the cable during the remainder of the rescue when the man is pulled upward at a constant velocity, you need to consider the balanced forces acting on the system.
When the man is pulled upward at a constant velocity, the net force acting on him is zero. This means that the tension in the cable must be equal to the weight of the man.
The tension in the cable is determined by the weight of the man, which is given as 868 N. Therefore, the tension in the cable during the remainder of the rescue when the man is pulled upward at a constant velocity is also 868 N.
So, the answer is:
(b) The tension during the remainder of the rescue when the man is pulled upward at a constant velocity is 868 N.