Consider the reaction between acetylene, C2H2, and oxygen in a welding torch: If 5.4 moles of acetylene react with sufficient oxygen, how many grams of CO2 will be formed?
2C2H2 + 5O2 ==> 4CO2 + 2H2O
Using the coefficients in the balanced equation, convert mols C2H2 to mols CO2.
Then convert mols CO2 t5o grams; g CO2 = mols CO2 x molar mass CO2.
how do I figure this out
2C2H6+7O2-->4CO2+6H2O,
To find the number of grams of CO2 formed, we need to determine the mole ratio between acetylene (C2H2) and CO2 in the balanced chemical equation. The balanced equation for the reaction between acetylene and oxygen to form CO2 and water is:
2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O
From the balanced equation, we can see that the mole ratio between acetylene (C2H2) and CO2 is 2:4, or 1:2.
Given that there are 5.4 moles of acetylene, we can use the mole ratio to find the number of moles of CO2 formed.
Number of moles of CO2 = 5.4 moles C2H2 × (2 moles CO2 / 1 mole C2H2)
= 10.8 moles CO2
Now, we need to determine the molar mass of CO2, which is the sum of the atomic masses of one carbon atom (C) and two oxygen atoms (O).
Molar mass of CO2 = (12.01 g/mol × 1) + (16.00 g/mol × 2)
= 12.01 g/mol + 32.00 g/mol
= 44.01 g/mol
Finally, we can calculate the mass of CO2 formed by multiplying the number of moles of CO2 formed by its molar mass.
Mass of CO2 = 10.8 moles CO2 × 44.01 g/mol
= 475.95 g
Therefore, if 5.4 moles of acetylene react with sufficient oxygen, approximately 475.95 grams of CO2 will be formed.
To find the number of grams of CO2 that will be formed in the reaction, we need to use mole-to-mole ratios and molar masses.
The balanced chemical equation for the reaction between acetylene (C2H2) and oxygen (O2) to form carbon dioxide (CO2) is:
2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O
From the balanced equation, we can see that 2 moles of acetylene react to form 4 moles of CO2. Therefore, for every 2 moles of acetylene, we can expect to produce 4 moles of CO2.
Given that there are 5.4 moles of acetylene, we can set up a ratio to find the moles of CO2 formed:
(5.4 moles C2H2) x (4 moles CO2 / 2 moles C2H2) = 10.8 moles CO2
Now, to find the mass of CO2 formed, we need to multiply the moles of CO2 by the molar mass of CO2. The molar mass of CO2 is approximately 44 g/mol.
(10.8 moles CO2) x (44 g CO2 / 1 mole CO2) = 475.2 grams of CO2
Therefore, approximately 475.2 grams of CO2 will be formed when 5.4 moles of acetylene react with sufficient oxygen in the welding torch.