A ball is thrown from an initial height of 130 feet with an initial upward velocity of 35ft/s . The ball's height H (in feet) after T seconds is given by the following
h=130-6t-16t^2
To find the height of the ball after a given time, we substitute the value of time (T) into the equation h = 130 - 6t - 16t^2.
Let's use this formula to calculate the height after 3 seconds.
Step 1: Substitute 3 for T in the equation.
h = 130 - 6 * 3 - 16 * (3)^2
h = 130 - 18 - 16 * 9
h = 130 - 18 - 144
h = -32
Therefore, the height of the ball after 3 seconds is -32 feet.
wrong
h = 130 + 35t - 16t^2