A falling 50-kg skydiver experiences an upward acceleration of 6.2 m/s2 when she opens her parachute. Show (by calculation) how much drag force is produced by the parachute.
(50*10)=500N
(10+6.2)=16.2m/sec^2
force = (ma)=50*16.2=810N
Wow, that skydiver must have really wanted to slow down! Okay, let's calculate the drag force produced by the parachute. We know that the mass of the skydiver is 50 kg, and the upward acceleration experienced when she opens her parachute is 6.2 m/s². So, the net force acting on her is given by the equation force = mass * acceleration. Plugging in the numbers, we get force = 50 kg * 6.2 m/s², which gives us a force of 310 N. And there you have it, the drag force produced by the parachute is 310 N. Let's hope it's enough to keep her floating gently down to the ground.
To calculate the drag force produced by the parachute, we need to use the equation:
Force = mass * acceleration
The mass of the skydiver is given as 50 kg and the acceleration she experiences when she opens her parachute is 6.2 m/s².
Plugging in these values into the equation, we have:
Force = 50 kg * 6.2 m/s²
= 310 N
Therefore, the drag force produced by the parachute is 310 N.
To calculate the drag force produced by the parachute, you need to use the equation F = ma, where F is the force (drag force in this case), m is the mass of the skydiver, and a is the acceleration.
First, let's calculate the weight of the skydiver, which is simply the product of mass (50 kg) and acceleration due to gravity (10 m/s^2). So, the weight is 500 N.
Next, we need to calculate the net force acting on the skydiver when the parachute is open. The upward acceleration is given as 6.2 m/s^2. To get the net force, we need to consider the weight acting downwards and the upward acceleration due to the parachute.
The net acceleration is the sum of the upward acceleration due to the parachute (6.2 m/s^2) and the acceleration due to gravity (10 m/s^2). So, the net acceleration is 16.2 m/s^2.
Now, we can calculate the net force acting on the skydiver. Using the equation F = ma, where m is the mass of the skydiver (50 kg) and a is the net acceleration (16.2 m/s^2), we have:
Force = (50 kg) * (16.2 m/s^2) = 810 N
Therefore, the drag force produced by the parachute is 810 N.