Please show me how to find ordered pairs.
2x+y =8
Thanks.
pick any value for x, say 20
Then 2*20+y = 8
40+y = 8
y = -32
So, (20,-32) is one pair
Or, pick any value for y, say 0
Then 2x+0=8
x=4
So, (4,0) is another pair
To find ordered pairs that satisfy the equation 2x+y=8, you can follow these steps:
1. Choose a value for x. Let's say, for example, x = 0.
2. Substitute the value of x into the equation and solve for y:
2(0) + y = 8
0 + y = 8
y = 8
3. The ordered pair for this solution is (0, 8), since x = 0 and y = 8.
Repeat these steps with different values of x to find more ordered pairs that satisfy the equation.
To find ordered pairs that satisfy the equation 2x + y = 8, you can use a method called substitution. Here are the steps:
1. Choose a value for x. Let's pick any number.
2. Substitute the chosen value of x into the equation, and solve for y.
3. Write down the ordered pair (x, y) with the chosen value of x and the corresponding value of y.
Let's go through an example to illustrate the process:
1. Let's choose x = 2.
2. Substitute this value into the equation: 2(2) + y = 8.
Solve for y: 4 + y = 8.
Subtract 4 from both sides: y = 8 - 4 = 4.
3. The ordered pair is (2, 4).
Now, you can choose any other value for x and repeat the process to find more ordered pairs. For example:
1. Let's choose x = 0.
2. Substitute this value into the equation: 2(0) + y = 8.
Solve for y: 0 + y = 8.
Therefore, y = 8.
3. The ordered pair is (0, 8).
Repeat these steps for different values of x, and you can find multiple ordered pairs that satisfy the equation 2x + y = 8.