What is the separation of colors in a rainbow produced by?

(Points : 1)
different diffraction for different wavelengths

different interference for different wavelengths <---

different refraction for different wavelengths

difference in total internal reflection for different wavelengths

Question 5.5. A ray of red light traveling through air strikes a block of quartz at an angle of incidence of 40°. If that light travels through the quartz and then enters a large crystal of sodium chloride (salt), what is the angle of refraction of the light in the sodium chloride? Quartz has an index of refraction of 1.46, while sodium chloride's index of refraction is 1.54.
(Points : 1)
25°

82°

40° <---

46°

Question 6.6. Light striking an object with index of refraction 1.24 has wavelength 440 nm. What is the wavelength of light in the object?
(Points : 1)
355 nm

546 nm

440 nm <--

220 nm

The last question is. 355 nm b/c 440/1.24= 355 but I still need help on the other questions please

different refraction for different wavelengths

25°

355 nm

5.5- is actually 25°

6.6-is 355 nm
The other question u were correct

To answer the questions:

1. The separation of colors in a rainbow is produced by different refraction for different wavelengths. When sunlight passes through raindrops, the different colors of light refract at slightly different angles, causing them to separate and form a rainbow.

2. For the given scenario, the angle of incidence is 40° and the light is traveling from quartz (n=1.46) to sodium chloride (n=1.54). We can use Snell's Law to find the angle of refraction. Snell's Law states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the indices of refraction. So, by plugging in the given values, we can solve for the angle of refraction. In this case, the angle of refraction in sodium chloride is also 40°.

3. In this question, the light is traveling through an object with an index of refraction of 1.24, and the given wavelength of light is 440 nm. The wavelength of light in a medium is given by λm = λ0 / n, where λm is the wavelength in the medium, λ0 is the wavelength in vacuum, and n is the index of refraction. By plugging in the values, we find that the wavelength of light in the object is also 440 nm.

Therefore, the correct answers are:

1. The separation of colors in a rainbow is produced by different refraction for different wavelengths.
2. The angle of refraction of the light in sodium chloride is 40°.
3. The wavelength of light in the object is 440 nm.