how many grams of sugar would be needed to give a 50.00 mL solution of FD&C Red Dye a concentration of 6.0% sugar?
I'm going to assume that this is mass/volume percent:
m/v%=(g/mL)*100
6.0%=(x g/50mL)*100
(6.0/100)*50=x g
Solve for x g
Which should be 3g, I believe.
Is this % w/w or % w/v? I'll assume % w/v
% w/v = (grams solute/50 mL)*100
Solve for grams.
To calculate the amount of sugar needed to achieve a 6.0% concentration in a 50.00 mL solution of FD&C Red Dye, we can use the following formula:
Amount of sugar (in grams) = volume of solution (in mL) * concentration of sugar (in decimal form)
Step 1: Convert the concentration from percentage to decimal form:
6.0% = 6.0/100 = 0.06
Step 2: Substitute the values into the formula and calculate:
Amount of sugar = 50.00 mL * 0.06 = 3.00 grams
Therefore, you would need 3.00 grams of sugar to give a 50.00 mL solution of FD&C Red Dye a concentration of 6.0% sugar.