Calculate the molarity of a solution made by adding 47.2g of NaNO3 to a flask and dissolving it with water to create a total volume of 1.80L .
mols = grams/molar mass
M = mols/L
To calculate the molarity of a solution, you need to know the number of moles of the solute (NaNO3) and the volume of the solution in liters.
Here's how to calculate the molarity of the solution:
Step 1: Convert the mass of NaNO3 to moles.
To do this, you need to know the molar mass of NaNO3. The molar mass of NaNO3 is the sum of the atomic masses of sodium (Na), nitrogen (N), and three oxygen (O) atoms.
Molar mass of NaNO3 = (22.99 g/mol for Na) + (14.01 g/mol for N) + (3 * 16.00 g/mol for O) = 85.00 g/mol
To convert the mass of NaNO3 to moles, divide the mass by its molar mass:
Number of moles of NaNO3 = 47.2 g / 85.00 g/mol = 0.554 moles
Step 2: Calculate the molarity.
Molarity is defined as the number of moles of solute divided by the volume of the solution in liters:
Molarity (M) = Number of moles of solute / Volume of solution (in liters)
In this case, the number of moles of NaNO3 is 0.554 moles and the volume of the solution is 1.80 L.
Molarity (M) = 0.554 moles / 1.80 L ≈ 0.308 M
Therefore, the molarity of the solution is approximately 0.308 M (Molar).
Keep in mind that the molarity is a measure of the concentration of the solution in moles per liter (mol/L or M).