1.A square has side lengths of 3 units. One of its vertices is at (5, -2). Which of the following are possible coordinates of another vertex?
a)(9,-2)
b)(8,-2)
c)(5,5)
d)(5,-1)
idk can someone help i am confused
I am confused can anyone please help me?
Which of the x values has been increased by 3 units without changing its height ,
that is 5+3 = ????
I think it is D or C.
Sure, I can help you with that! To find a possible coordinate of another vertex of the square, we can use the given information that one vertex is located at (5, -2) and the side length of the square is 3 units.
To start, let's plot the given vertex on a coordinate grid. Place a point at (5, -2):
5 *
|
4 |
|
3 |
|
2 |
|
1 |
|
0---------------------------------------
-2 -1 0 1 2 3 4 5 6 7 8 9
Next, since the sides of a square are equal in length, we can use this property to find another possible coordinate.
We know that the x-coordinate of the given vertex is 5. If we move 3 units to the right from this point, we get the x-coordinate of the other vertex. Therefore, the x-coordinate of the other vertex is 5 + 3 = 8.
Now, let's look at the answer choices:
a) (9, -2)
b) (8, -2)
c) (5, 5)
d) (5, -1)
The x-coordinate of the other vertex is 8, so we can eliminate options a), c), and d) since none of them have an x-coordinate of 8.
This leaves us with option b) (8, -2) as the possible coordinate of another vertex of the square.
Therefore, the correct answer is b) (8, -2).