How would i go about finding the x and y intercepts of this eqaution?

f(x)=3x/4x+2

To find the x-intercept of an equation, set y (or f(x)) to zero and solve for x. The x-intercept is the point where the line crosses the x-axis.

To find the y-intercept of an equation, set x to zero and solve for y (or f(x)). The y-intercept is the point where the line crosses the y-axis.

Let's find the x-intercept first:
1. Set y (or f(x)) to zero: 3x/4x+2 = 0
2. Since the numerator is already zero (3x = 0), the only way for the fraction to be zero is if the denominator is nonzero.
3. Set the denominator 4x + 2 to zero: 4x + 2 = 0
4. Solve for x: Subtract 2 from both sides: 4x = -2, then divide by 4: x = -1/2.

Therefore, the x-intercept of the equation f(x) = 3x/4x+2 is x = -1/2.

Now let's find the y-intercept:
1. Set x to zero: f(0) = 3(0)/(4(0)+2)
2. Simplify the equation: f(0) = 0/2 = 0.

Therefore, the y-intercept of the equation f(x) = 3x/4x+2 is y = 0 (or the point (0, 0)).