Find the perimeter of a right triangle with legs of 20 cm, and 21 cm.
a.882
b.82
c.70
d.47
I have no clue what to do. Can somebody help me with this please?
First you have to use the Pythagorean Theorem to find the hypotenuse of the right triangle. In this formula, c is the hypotenuse.
a^2 + b^2 = c^2
20^2 + 21^2 = c^2
400 + 441 = c^2
841 = c^2
29 = c
Now, add 20 + 21 + 29 to find the perimeter.
To find the perimeter of a right triangle, you need to add the lengths of all three sides of the triangle.
In this case, the right triangle has two legs measuring 20 cm and 21 cm. The third side is the hypotenuse of the triangle, which can be found using the Pythagorean theorem.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). It can be written as: c^2 = a^2 + b^2.
Plugging in the lengths of the legs into the Pythagorean theorem:
c^2 = 20^2 + 21^2
c^2 = 400 + 441
c^2 = 841
Taking the square root of both sides to solve for c:
c = √841
c = 29
So, the length of the hypotenuse is 29 cm.
Now let's calculate the perimeter:
Perimeter = a + b + c
Perimeter = 20 cm + 21 cm + 29 cm
Perimeter = 70 cm
Therefore, the perimeter of the right triangle is 70 cm.
According to the options provided, the correct answer is c.70.