716-{(1950/5 of 3)-(4+217/7)}
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716-{(1950÷5of3)-(4+217÷7)}
Alexander the great
Simplify: 716 - { ( 1950 ÷ 5 of 3 ) -( 4+ 217÷7) }
Solution
716-{(1950/5 of 3)-(4+217/7)}
of just means times, so you have
716-{(1950/5 * 3)-(4+217/7)}
716-{(390*3)-(4+31)}
716-{1170-35}
716-1135
-419