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How many moles of li2so4 is required to prepare 300ml of a 0.5 m solution
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H2SO4(aq) + 2LiOH(aq) → Li2SO4(aq) + 2H2O(l)
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Then 3.2 mols LiOH will form 3.2/2 = 1.6 mols Li2SO4 grams Li2SO4 = mols x molar mass = ? (Li2SO4)
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hi, i was wondering if anyone could help me with this problem? i am having some difficulty with it. thanks.
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molarity = #mols/Liter of solution. grams = #mols x molar mass. So use equation 1, plug in M and L
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A sample of sodium sulfate, Li2SO4, contains 6.78 x 10^23 formula units.
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Calculate the mass of solute required to prepare ib the solution 200cm^3 of solution containig 0.50 mol dm ^-3
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