In 1993, Cuban athlete Javier Sotomayor set the world record for the high jump. the gravitational potential energy associated with Sotomayor's jump was 1970 J. Sotomayor's mass was 82.0 kg. How high did Sotomayor Jump?
We use the formula
PE = mgh
where
PE = potential energy (J)
m = mass (kg)
g = acceleration due to gravity = 9.8 m/s^2
h = height (m)
Substituting,
1970 = 82(9.8)(h)
h = 2.45 m
hope this helps~ `u`
Gravitational energy (in joules)
= mgh
where
m=mass (k)
g=acceleration due to gravity (m/s²)
h=height (m)
Solve for h.
To find the height of Sotomayor's jump, we need to use the formula for gravitational potential energy:
Potential Energy = m * g * h
where m is the mass of the object (in this case, Sotomayor's mass), g is the acceleration due to gravity, and h is the height.
In the given information, the potential energy is 1970 J and the mass is 82.0 kg. The acceleration due to gravity is approximately 9.8 m/s^2.
To solve for h, we rearrange the formula:
h = Potential Energy / (m * g)
h = 1970 J / (82.0 kg * 9.8 m/s^2)
Now, we can calculate the height:
h = 1970 J / (803.6 kg * 9.8 m/s^2)
h ≈ 2.511 meters
Therefore, Sotomayor jumped approximately 2.511 meters high.