n2+3I2>2NI3 if you have 28g of N2how many grams of NI3 will you be able to make?
To determine the grams of NI3 that can be made from 28g of N2, we need to calculate the molar mass of N2 and NI3 and then use stoichiometry to find the corresponding amounts.
1. Determine the molar mass of N2:
- The molar mass of Nitrogen (N) is approximately 14.01 g/mol.
- Since N2 consists of two nitrogen atoms, the molar mass of N2 is: 2 * 14.01 g/mol = 28.02 g/mol.
2. Use stoichiometry to find the molar ratio between N2 and NI3 based on the balanced equation:
- The chemical equation states that 1 mole of N2 reacts to form 2 moles of NI3.
- Therefore, the molar ratio between N2 and NI3 is 1:2.
3. Calculate the moles of N2 in 28g:
- Moles = Mass / Molar mass
- Moles of N2 = 28g / 28.02 g/mol = 1 mole of N2.
4. Use the molar ratio to find the moles of NI3:
- Since the molar ratio between N2 and NI3 is 1:2, 1 mole of N2 will react to form 2 moles of NI3.
- Therefore, the moles of NI3 produced will also be 1 mole x 2 = 2 moles of NI3.
5. Calculate the mass of NI3 produced:
- Mass = Moles x Molar mass
- Moles of NI3 = 2 moles
- Molar mass of NI3 can be calculated by summing the molar masses of Nitrogen (N) and Iodine (I), each occurring three times in the formula:
- Nitrogen (N) molar mass = 14.01 g/mol
- Iodine (I) molar mass = 126.9 g/mol
- Molar mass of NI3 = 3 * 14.01 g/mol + 3 * 126.9 g/mol = 394.27 g/mol
- Mass of NI3 = 2 moles x 394.27 g/mol = 788.54 g
Therefore, you will be able to produce approximately 788.54 grams of NI3 from 28 grams of N2.