physics

A 0.205 kg bird flying along at 7.8 m/s sees a 0.029 kg insect heading straight toward it with a speed of 15 m/s (as measured by an observer on the ground, not by the bird). The bird opens its mouth wide and enjoys a nice lunch. What is the bird's speed immediately after swallowing the insect?

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  1. M1*V1 + M2*V2 = M1*V + M2*V
    0.205*7.8 + 0.029*15 = 0.205*V + 0.029*V
    Solve for V.

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    posted by Henry

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