A student mixed two clear liquids together in a beaker and a solid precipitate formed. His data is shown in the table below.
Liquid reactant A = 10 g
Liquid reactant B = 17 g
Beaker + solid product= 32 g
What is the mass of the beaker?
A. 5 g
B. 10 g
C. 15 g
D. 17 g
E. 32 g
Is the answer A?
Thank you
pls help me
It is A.
all you need to do is add up the two liquids and subtract
32 with the answer you got from the liquids.
Someone on another post said it was A. 5g. Haven't tried it but, I hope it works.
Yea, it's A. 5g
I got 100% :3
Thanks!
To find the mass of the beaker, we can use the information given in the question.
First, we need to determine the total mass of the reactants, which is Liquid reactant A + Liquid reactant B:
Total mass of reactants = 10 g + 17 g = 27 g
Next, we subtract the total mass of the reactants from the total mass of the beaker and solid product to find the mass of the beaker:
Mass of beaker = Total mass of beaker and solid product - Total mass of reactants
Mass of beaker = 32 g - 27 g
Mass of beaker = 5 g
Therefore, the mass of the beaker is 5 g, which means the correct answer is option A.