Calculate the molarity of 5.8 L of NaCl solution that contains 65 g of NaCl

Find 1 Mol of NaCl (using the periodic table)

That amount of g in 1 litre of water is a 1.0 Mol/L solution of NaCl (that is its molarity)

Compare that to what you have per litre

Please obey Jiskha rules and put your subject matter in the subject matter space if you want a chemistry tutor to see your post.

To calculate the molarity (M) of a solution, you need to know the number of moles of solute (NaCl) and the volume of the solution (in liters). Here's the step-by-step process to find the molarity:

Step 1: Calculate the number of moles of NaCl:
To do this, you need to convert the given mass of NaCl (65 g) to moles using its molar mass. The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is 22.99 g/mol for Na and 35.45 g/mol for Cl.

Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

Number of moles of NaCl = mass of NaCl / molar mass of NaCl
= 65 g / 58.44 g/mol
≈ 1.113 mol

Step 2: Calculate the volume of the solution in liters:
The given volume of the solution is 5.8 L.

Step 3: Calculate the molarity of the solution:
Molarity (M) = moles of solute / volume of solution (in liters)
= 1.113 mol / 5.8 L
≈ 0.191 M

Therefore, the molarity of the NaCl solution is approximately 0.191 M.

To calculate the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). Here's how you can find the molarity of the 5.8 L NaCl solution:

1. Convert the mass of NaCl to moles:
- The molar mass of NaCl is 58.44 g/mol (Na: 22.99 g/mol; Cl: 35.45 g/mol).
- Divide the given mass (65 g) by the molar mass to get the number of moles of NaCl:
65 g / 58.44 g/mol = 1.115 mol

2. Calculate the molarity (M):
- Molarity is defined as moles of solute divided by liters of solution.
- Divide the number of moles of NaCl (1.115 mol) by the volume of the solution (5.8 L):
M = 1.115 mol / 5.8 L ≈ 0.192 M

Therefore, the molarity of the NaCl solution is approximately 0.192 M.