You have 100 mL of a 0.450 M sulfuric acid solution, but you now need to add NaOH to make the solution basic. How much NaOH ( in grams) will you need to add to make the solution have a pH of 13.0? The units are grams of NaOH.

Question

You have 100 mL of a 0.450 M sulfuric acid solution, but you now need to add NaOH to make the solution basic. How much NaOH ( in grams) will you need to add to make the solution have a pH of 13.0? The units are grams of NaOH.

Answer 1

2NaOH + H2SO4 ==> Na2SO4 + 2H2O

How many mols H2SO4 do you have? That's M x L = >
How many mols NaOH do you need to neutralize that? That's mols NaOH = 2x mols H2SO4 from the coefficients in the balanced equation.
At that point you have a pH = 7 (neutral solution with 100 mL (0.1L) solution We assume there is no volume increase with the addition of the solid NaOH. grams NaOH to get to that point is g = mols x molar mass = ?

Now subtract (OH^-) = ? with pH 13 from (OH^-) with pH = 7, convert that to g NaOH.
Post your work if you get stuck.